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Python OOPs Concept

Python Overloading

python_overloading

In the method overloading, methods or functions must have the same name and different signatures.

Consider below example:

>>> def add(a, b):
	return a + b

>>> def add(a, b, c):
	return a + b + c

>>> add(4, 5)
Traceback (most recent call last):
  File "", line 1, in 
    add(4, 5)
TypeError: add() missing 1 required positional argument: 'c'

It is because Python keeps only the latest definition of a method you declare to it. This code doesn't make a call to the version of add() that takes in two arguments to add. So we find it safe to say Python doesn’t support method overloading.

But to make this happen in Pythonic way, we can write the function like below.

>>> def add(instanceOf, *args):
	if instanceOf == 'int':
		res = 0
	if instanceOf == 'str':
		res = ''
	for i in args:
		res += i
	return res

>>> add('int', 1, 2, 3)
6
>>> add('int', 1, 2)
3
>>> add('str', 'Hello', ' World')
'Hello World'
>>> 

It is to note that it isn't method overloading but simply use of default arguments.

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Venkat on Sep 01, 2020 at 12:09 am


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