Given an m x n integer matrix matrix, if an element is 0, set its entire row and column to 0's, and return the matrix.
You must do it in place.
Example 1:
Input: matrix = [[1,1,1],[1,0,1],[1,1,1]] Output: [[1,0,1],[0,0,0],[1,0,1]]
Example 2:
Input: matrix = [[0,1,2,0],[3,4,5,2],[1,3,1,5]] Output: [[0,0,0,0],[0,4,5,0],[0,3,1,0]]
Constraints:
m == matrix.lengthn == matrix[0].length1 <= m, n <= 200-231 <= matrix[i][j] <= 231 - 1
Follow up:
O(mn) space is probably a bad idea.O(m + n) space, but still not the best solution.For to solve it in O(mn), use a copy of given matrix and go through every element of original matrix and update the copy matrix's row and column to zero if a zero if found in original matrix.
O(m + n) Solution:
class Solution:
    def setZeroes(self, matrix: List[List[int]]) -> None:
        """
        Do not return anything, modify matrix in-place instead.
        """
        ROWS, COLS = len(matrix), len(matrix[0])
        rows = [0] * ROWS
        cols = [0] * COLS
        for r in range(ROWS):
            for c in range(COLS):
                if matrix[r][c] == 0:
                    rows[r] = 1
                    cols[c] = 1
        for c in range(COLS):
            for R in range(len(rows)):
                if rows[R] == 1:
                    matrix[R][c] = 0
        for r in range(ROWS):
            for C in range(len(cols)):
                if cols[C] == 1:
                    matrix[r][C] = 0
O(1) Solution:class Solution:
    def setZeroes(self, matrix: List[List[int]]) -> None:
        """
        Do not return anything, modify matrix in-place instead.
        """
        ROWS, COLS = len(matrix), len(matrix[0])
   
        rowZero = False
        
        for r in range(ROWS):
            for c in range(COLS):
                if matrix[r][c] == 0:
                    matrix[0][c] = 0
                    if r > 0:
                        matrix[r][0] = 0
                    else:
                        rowZero = True
        for r in range(1, ROWS):
            for c in range(1, COLS):
                if matrix[0][c] == 0 or matrix[r][0] == 0:
                    matrix[r][c] = 0
        if matrix[0][0] == 0:
            for r in range(ROWS):
                matrix[r][0] = 0
        if rowZero:
            for c in range(COLS):
                matrix[0][c] = 0
                        
 
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